(4x+4)^1/3-(7x-1)^1/3=0

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Solution for (4x+4)^1/3-(7x-1)^1/3=0 equation: 


x in (-oo:+oo)

((4*x+4)^1)/3-(((7*x-1)^1)/3) = 0

(4*x+4)/3-((7*x-1)/3) = 0

(4*x+4)/3+(-1*(7*x-1))/3 = 0

4*x-1*(7*x-1)+4 = 0

5-3*x = 0

(5-3*x)/3 = 0

(5-3*x)/3 = 0 // * 3

5-3*x = 0

5-3*x = 0 // - 5

-3*x = -5 // : -3

x = -5/(-3)

x = 5/3

x = 5/3

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